Read an XML file in Java

For previously been discussed about how to convert data to xml, we now discuss for how to parse xml. This is a simple way for parsing the xml file.
The following example code :
XML File :

<table>

−

<Row>

<kecamatan> KARANG PILANG </kecamatan>

<laki>74</laki>

</Row>

−

<Row>

<kecamatan> WONOCOLO </kecamatan>

<laki>69</laki>

</Row>

−

<Row>

<kecamatan> RUNGKUT </kecamatan>

<laki>115</laki>

</Row>

−

<Row>

<kecamatan> WONOKROMO </kecamatan>

<laki>138</laki>

</Row>

</table>

view raw XMLOuput hosted with ❤ by GitHub

Output :

	Root element table
	Total no of people : 5
	Kecamatan : KARANG PILANG
	Laki-Laki : 74
	Kecamatan : WONOCOLO
	Laki-Laki : 69
	Kecamatan : RUNGKUT
	Laki-Laki : 115
	Kecamatan : WONOKROMO
	Laki-Laki : 138
	Kecamatan : TEGALSARI
	Laki-Laki : 60

view raw output hosted with ❤ by GitHub

Java Code:

	import java.io.File;
	import org.w3c.dom.Document;
	import org.w3c.dom.*;
	import javax.xml.parsers.DocumentBuilderFactory;
	import javax.xml.parsers.DocumentBuilder;
	import org.xml.sax.SAXException;
	import org.xml.sax.SAXParseException;
	public class ReadAndPrintXMLFile{
	public static void main (String argv []){
	try {
	DocumentBuilderFactory docBuilderFactory = DocumentBuilderFactory.newInstance();
	DocumentBuilder docBuilder = docBuilderFactory.newDocumentBuilder();
	Document doc = docBuilder.parse (new File("c:/cobaya.xml")); //path of file XML
	doc.getDocumentElement ().normalize ();
	System.out.println ("Root element " +
	doc.getDocumentElement().getNodeName());
	NodeList listOfPersons = doc.getElementsByTagName("Row");
	int totalPersons = listOfPersons.getLength();
	System.out.println("Total no of people : " + totalPersons);
	for(int s=0; s<listOfPersons.getLength() ; s++){
	Node firstPersonNode = listOfPersons.item(s);
	if(firstPersonNode.getNodeType() == Node.ELEMENT_NODE){
	Element firstPersonElement = (Element)firstPersonNode;
	//-------
	NodeList firstNameList = firstPersonElement.getElementsByTagName("kecamatan"); //node
	Element firstNameElement = (Element)firstNameList.item(0);
	NodeList textFNList = firstNameElement.getChildNodes();
	System.out.println("Kecamatan : " +
	((Node)textFNList.item(0)).getNodeValue().trim());
	//-------
	NodeList lastNameList = firstPersonElement.getElementsByTagName("laki"); //Node
	Element lastNameElement = (Element)lastNameList.item(0);
	NodeList textLNList = lastNameElement.getChildNodes();
	System.out.println("Laki-Laki : " +
	((Node)textLNList.item(0)).getNodeValue().trim());
	}//end of if clause
	}//end of for loop with s var
	}catch (SAXParseException err) {
	System.out.println ("** Parsing error" + ", line "
	+ err.getLineNumber () + ", uri " + err.getSystemId ());
	System.out.println(" " + err.getMessage ());
	}catch (SAXException e) {
	Exception x = e.getException ();
	((x == null) ? e : x).printStackTrace ();
	}catch (Throwable t) {
	t.printStackTrace ();
	}
	//System.exit (0);
	}//end of main
	}

view raw parsingXML hosted with ❤ by GitHub

There are better implementations of reading XML files which would work for any XML file. The above one would require a few changes every time the XML tag names change. But this is much more simpler than the other programs.